6mols of N2 are mixed with 12mol H2, according to the following equation.
N2+3H2----> 2NH3
a) which is the limiting reactant?
B) which chemical is in excess?
c) how many moles of excess reactant is left over?
d) how many moles of NH3 can be produced?
e)if only 6.4 mols of NH3 are produced What is the percent yield?
1 answer