Let's analyze the reaction you've provided:
\[ 6 \text{CO}_2 + 6 \text{H}_2\text{O} \rightarrow \text{C}6\text{H}{12}\text{O}_6 + 6 \text{O}_2 \]
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How many molecules of carbon dioxide are involved in this reaction?
- There are 6 molecules of carbon dioxide (CO₂) involved in this reaction.
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How many molecules of sugar are produced in this reaction?
- The reaction produces 1 molecule of glucose (C₆H₁₂O₆).
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How many atoms of carbon are on the left of the equation? How many on the right?
- On the left side (reactants), each molecule of CO₂ has 1 carbon atom. Since there are 6 molecules of CO₂, there are \(6 \times 1 = 6\) carbon atoms.
- On the right side (products), each molecule of glucose (C₆H₁₂O₆) has 6 carbon atoms. Therefore, there are 6 carbon atoms on the right side.
In summary:
- 6 molecules of CO₂ are involved.
- 1 molecule of sugar (C₆H₁₂O₆) is produced.
- 6 carbon atoms are present on both sides of the equation.