Asked by pickles
6cm
8cm
10cm
Determine the volume of the figure if it were dilated using a scale factor of 2.
(1 point)
cm3
8cm
10cm
Determine the volume of the figure if it were dilated using a scale factor of 2.
(1 point)
cm3
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine the volume of a figure when it is dilated using a scale factor, we need to understand how dilation affects volume.
When an object is dilated by a scale factor \( k \), the volume of the new figure becomes \( k^3 \) times the volume of the original figure.
First, let's find the volume of the original figure. Based on the provided dimensions of 6 cm, 8 cm, and 10 cm, it appears to be a rectangular prism. The formula for the volume \( V \) of a rectangular prism is given by:
\[
V = \text{length} \times \text{width} \times \text{height}
\]
Substituting the given dimensions:
\[
V = 6 \, \text{cm} \times 8 \, \text{cm} \times 10 \, \text{cm} = 480 \, \text{cm}^3
\]
Next, we apply the scale factor of \( k = 2 \) to find the new volume:
\[
\text{New Volume} = k^3 \times V = 2^3 \times 480 \, \text{cm}^3 = 8 \times 480 \, \text{cm}^3
\]
Calculating the new volume:
\[
\text{New Volume} = 3840 \, \text{cm}^3
\]
Thus, the volume of the figure after dilation is:
\[
\boxed{3840} \, \text{cm}^3
\]
When an object is dilated by a scale factor \( k \), the volume of the new figure becomes \( k^3 \) times the volume of the original figure.
First, let's find the volume of the original figure. Based on the provided dimensions of 6 cm, 8 cm, and 10 cm, it appears to be a rectangular prism. The formula for the volume \( V \) of a rectangular prism is given by:
\[
V = \text{length} \times \text{width} \times \text{height}
\]
Substituting the given dimensions:
\[
V = 6 \, \text{cm} \times 8 \, \text{cm} \times 10 \, \text{cm} = 480 \, \text{cm}^3
\]
Next, we apply the scale factor of \( k = 2 \) to find the new volume:
\[
\text{New Volume} = k^3 \times V = 2^3 \times 480 \, \text{cm}^3 = 8 \times 480 \, \text{cm}^3
\]
Calculating the new volume:
\[
\text{New Volume} = 3840 \, \text{cm}^3
\]
Thus, the volume of the figure after dilation is:
\[
\boxed{3840} \, \text{cm}^3
\]
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