Asked by DAN
                Consider the reaction.
PbCO3(s)<--> PbO(s) + CO2(g).
calculate the equilibrium pressure of CO2 in the system at the following temperatures.(IN atm)
(a) 270°C
(b) 480°C
..... delta Hf(KJ/mol).. d.Gf(KJ/mol).. S(J/mol-K)
PbCO3(s)..-699.1 .. -625.5 .. 131.0
PbO(s) .. -217.3 .. -187.9 .. 68.70
CO2(g) ... -393.5 .. -394.4 .. 213.6
Please help me!!! U could help me on the first one then i'll do the second one myself
            
        PbCO3(s)<--> PbO(s) + CO2(g).
calculate the equilibrium pressure of CO2 in the system at the following temperatures.(IN atm)
(a) 270°C
(b) 480°C
..... delta Hf(KJ/mol).. d.Gf(KJ/mol).. S(J/mol-K)
PbCO3(s)..-699.1 .. -625.5 .. 131.0
PbO(s) .. -217.3 .. -187.9 .. 68.70
CO2(g) ... -393.5 .. -394.4 .. 213.6
Please help me!!! U could help me on the first one then i'll do the second one myself
Answers
                    Answered by
            DrBob222
            
    I think you can calculate dGf for the reaction (n*dGf products)-n*dGo reactants) and from there dGo = -RTlnK. Solve for ln K at each T.
Then lnK = pCO2
    
Then lnK = pCO2
                    Answered by
            DAN
            
    So do i plug in 270C in kelvin as my temp in the first formula???
    
                    Answered by
            DrBob222
            
    yes
    
                    Answered by
            DAN
            
    i still don't get the right answer 
i have like 1.54*10-14
    
i have like 1.54*10-14
                    Answered by
            DrBob222
            
    What is the right answer? I calculated K and obtained 6.98E-5.
    
                    Answered by
            HURRR
            
    DURRRRR
    
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