Asked by DAN

Consider the reaction.
PbCO3(s)<--> PbO(s) + CO2(g).

calculate the equilibrium pressure of CO2 in the system at the following temperatures.(IN atm)

(a) 270°C

(b) 480°C

..... delta Hf(KJ/mol).. d.Gf(KJ/mol).. S(J/mol-K)
PbCO3(s)..-699.1 .. -625.5 .. 131.0

PbO(s) .. -217.3 .. -187.9 .. 68.70

CO2(g) ... -393.5 .. -394.4 .. 213.6


Please help me!!! U could help me on the first one then i'll do the second one myself
Answered by DrBob222
I think you can calculate dGf for the reaction (n*dGf products)-n*dGo reactants) and from there dGo = -RTlnK. Solve for ln K at each T.
Then lnK = pCO2
Answered by DAN
So do i plug in 270C in kelvin as my temp in the first formula???
Answered by DrBob222
yes
Answered by DAN
i still don't get the right answer
i have like 1.54*10-14
Answered by DrBob222
What is the right answer? I calculated K and obtained 6.98E-5.
Answered by HURRR
DURRRRR