Asked by Desiree
Ok ive been working on this problem for hours now, can you please tell me if i am correct? Thank You!
A gas occupies 340mL at 273 K and 610 torr. What final temperature would be required to increase the pressure to 1 atm, the volume being held constant?
P1/T1 = P2/T2
T2 = (T1*P2)/ P1
1 atm = 760 torr
So,
T2 = (273 K * 760 torr)/610 torr
T2 = 340 K
A gas occupies 340mL at 273 K and 610 torr. What final temperature would be required to increase the pressure to 1 atm, the volume being held constant?
P1/T1 = P2/T2
T2 = (T1*P2)/ P1
1 atm = 760 torr
So,
T2 = (273 K * 760 torr)/610 torr
T2 = 340 K
Answers
Answered by
DrBob222
340 K is correct.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.