Asked by Anonymous
Find the area of the regular polygon with the given radius. The radius of the square is 6 cm. area= apothem x perimeter/ 2
Answers
Answered by
Henry
a = y = apothem.
X = b/2 = 6/2 = 3.
r = 6 cm.
X^2 + Y^2 = r^2.
3^2 + Y^2 = 6^2.
9 + Y^2 = 36.
Y = 5.2 cm = a.
P = N * L = 6 * 6 = 36 cm.
A = aP/2 = 5.2 * 36 / 2 = 93.6 cm^2.
Alternate Method:
A = 2.60r^2 = 2.60 * 6^2 = 93.6 cm^2.
HEX. only.
X = b/2 = 6/2 = 3.
r = 6 cm.
X^2 + Y^2 = r^2.
3^2 + Y^2 = 6^2.
9 + Y^2 = 36.
Y = 5.2 cm = a.
P = N * L = 6 * 6 = 36 cm.
A = aP/2 = 5.2 * 36 / 2 = 93.6 cm^2.
Alternate Method:
A = 2.60r^2 = 2.60 * 6^2 = 93.6 cm^2.
HEX. only.
Answered by
esmerlin
Find a area 6cm
Answered by
Hilo guys
I'm sorry Henry, but that is wrong. The correct answer is actually 72.
I've done the complicated method with finding the apothem using the 45-45-90 triangle and then finding the side, and the perimeter. You'd have to substitute after that.
Thing is, the radius is also half of the diagonal. Meaning, the diagonal of this square would be 12. If the diagonal of the square of 12, the area is 72.
I hope this helps for anyone who sees this.
I've done the complicated method with finding the apothem using the 45-45-90 triangle and then finding the side, and the perimeter. You'd have to substitute after that.
Thing is, the radius is also half of the diagonal. Meaning, the diagonal of this square would be 12. If the diagonal of the square of 12, the area is 72.
I hope this helps for anyone who sees this.
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