x = - 3 , y = 8
QUADRANT II
arc tan ( sqrt 73 ) = 83.324408°
tan ( theta ) = - sqrt ( 73 )
theta = 180 ° - 83.324408°
theta = 96.675592°
theta = 96° 40' 32"
Find the cartesian coordinates
If (x,y) = (-3,8) then (r,theta) = ?
I already got r it is -sqrt73 but i cant seem to get theta right.
I got 110.556 but its wrong...please tell me how to do it thank you!!
3 answers
I don't agree with the above Ø
r = √(x^2+y^2)= √73
angle in standard position = arctan(8/3) = 69.44°
since (-3,8) is in II
Ø = 180-69.44 = 110.56°
(-3,8) ----> (√73, 110.56°)
r = √(x^2+y^2)= √73
angle in standard position = arctan(8/3) = 69.44°
since (-3,8) is in II
Ø = 180-69.44 = 110.56°
(-3,8) ----> (√73, 110.56°)
Both of these answers are still wrong