Asked by Mark
How many moles of ethylene glycol must be dissolved in 500 g of water (Kf = 1.86) to lower the freezing point to -5.00 0C?
Answers
Answered by
drbob222
delta T = K<sub>f</sub>*molality
Plug in 5.00 C for delta T, 1.86 for Kf and calculate molality.
Then molality x kg solvent x molar mass = grams.
You know molality, kg solvent, and molar mass. Calculate grams.
Post your work if you get stuck.
Plug in 5.00 C for delta T, 1.86 for Kf and calculate molality.
Then molality x kg solvent x molar mass = grams.
You know molality, kg solvent, and molar mass. Calculate grams.
Post your work if you get stuck.
Answered by
Mark
delta T = Kf*molality
Plug in 5.00 C for delta T, 1.86 for Kf and calculate molality.
Then molality x kg solvent x molar mass = grams.
You know molality, kg solvent, and molar mass. Calculate grams.
molar mass? where did u got the molar mass from ?
Plug in 5.00 C for delta T, 1.86 for Kf and calculate molality.
Then molality x kg solvent x molar mass = grams.
You know molality, kg solvent, and molar mass. Calculate grams.
molar mass? where did u got the molar mass from ?
Answered by
drbob222
answered above.
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