Asked by amanda

a triangluar garden has an area of 189 square feet. its height os 3 feet more than ots base. find the measure of the base.

Answers

Answered by Reiny
base ---- x
height ---- x+3

(1/2)x(x+3) = 189
x^2 + 3x = 378
x^2 + 3x - 378 = 0
(x-18)(x+21) = 0
x=18 or x=-21, but x can't be negative, so

x=18
base is 18, height is 21


check:area = (1/2)(18x21) = 189
Answered by Bosnian
A = Area

b = base

h = height


h = b + 3


A = b * h / 2 = 189 ft ^ 2

b * h / 2 = b * ( b + 3 ) / 2 = 189 Multiply both sides by 2

b * ( b + 3 ) = 378

b ^ 2 + 3 b - 378 = 0


The solutions are :

b = 18 ft

and

b = - 21 ft


The base can't be negative,so solution are :

b = 18 ft


h = b + 3 = 21 ft


Proof :

A = b * h / 2 = ( 18 * 21 ) / 2 = 378 / 2 = 189 ft ^ 2


If you don't know how to solve equaion

b ^ 2 + 3 b - 378 = 0



In google type:

quadratic equation online

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When page be open in rectangle type:

b ^ 2 + 3 b - 378 = 0

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