1.00 g of sodium is added to a large excess of water under conditions of constant pressure (1.00 atm) and constant temperature (25 °C ). The following reaction occurs:
2Na (s) +2H2O (l)------> 2NaOH (aq) +H2(g)
Delta H°rxn =-369 kJ/mol
Calculate the heat released after 1.00 g of Na(s) fully reacted. Atomic weight of Na is 23.0 g/mol
Could you please tell me how to do this! Thank you!
4 answers
369 kJ for 2*23 = 46 g. How much for 1.00 g? 369 x 1/46 = ?
I got an answer of 8.02...is this right? :)
No, but 8.02 kJ is. :-)
Ohhh yeahh haha thanks DrBob222! I really appreciate it! :D
2 answers