Asked by Anonymous

FIND THE SLOP of line containing points(-2,8) and (3,5)

Answers

Answered by Neil
-3/5
Answered by Bosnian
Two point form of linear equation :

y - y 1 = ( y 2 - y 1 ) * ( x - x 1 ) / ( x 2 - x 1 )

Te slope is explicitly given as

m = ( y 2 - y 1) / ( x 2 - x 1 )

In this case :

x 1 = - 2

x 2 = 3

y 1 = 8

y 2 = 5

m = ( y 2 - y 1 ) / ( x 2 - x 1 )

m = ( 5 - 8 ) / [ 3 - ( - 2 ) ]

m = - 3 / ( 3 + 2 )

m = - 3 / 5 = - 0.6

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