Question
FIND THE SLOP of line containing points(-2,8) and (3,5)
Answers
Neil
-3/5
Bosnian
Two point form of linear equation :
y - y 1 = ( y 2 - y 1 ) * ( x - x 1 ) / ( x 2 - x 1 )
Te slope is explicitly given as
m = ( y 2 - y 1) / ( x 2 - x 1 )
In this case :
x 1 = - 2
x 2 = 3
y 1 = 8
y 2 = 5
m = ( y 2 - y 1 ) / ( x 2 - x 1 )
m = ( 5 - 8 ) / [ 3 - ( - 2 ) ]
m = - 3 / ( 3 + 2 )
m = - 3 / 5 = - 0.6
y - y 1 = ( y 2 - y 1 ) * ( x - x 1 ) / ( x 2 - x 1 )
Te slope is explicitly given as
m = ( y 2 - y 1) / ( x 2 - x 1 )
In this case :
x 1 = - 2
x 2 = 3
y 1 = 8
y 2 = 5
m = ( y 2 - y 1 ) / ( x 2 - x 1 )
m = ( 5 - 8 ) / [ 3 - ( - 2 ) ]
m = - 3 / ( 3 + 2 )
m = - 3 / 5 = - 0.6