Asked by jose
you are standing on a 100m tall buiding above a street and your friend is standing vertically below the building. When you drop a stone, your friend simultaneously throws the identical stone as yours at a speed of 50m/s in the same straight line. Calculate the time taken for the stones to collide
Answers
Answered by
drwls
Let the heights of the two stones above the ground be Y1 and Y2.
Y1 = 100 - 4.9 t^2 (the dropped stone)
Y2 = -4.9 t^2 + 50 t (the thrown-upward stone)
Now set Y1 = Y2 and solve for t.
The t^2 terms drop out and you get an easy linear equation to solve.
Enjoy!
Y1 = 100 - 4.9 t^2 (the dropped stone)
Y2 = -4.9 t^2 + 50 t (the thrown-upward stone)
Now set Y1 = Y2 and solve for t.
The t^2 terms drop out and you get an easy linear equation to solve.
Enjoy!
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