Asked by bob
The ion HPO4–2 has both a conjugate base as well as a conjugate acid. The conjugate base of this ion is (1) while the conjugate acid is (2).
a) (1) = H2PO4– (2) H3PO4
b) (1) = PO4– (2) H2PO4+
c) (1) = PO4–3 (2) H2PO4–
d) (1) = HPO5–3 (2) HPO3–
e) (1) = H2PO4– (2) PO4–3
help! don't know what to do
a) (1) = H2PO4– (2) H3PO4
b) (1) = PO4– (2) H2PO4+
c) (1) = PO4–3 (2) H2PO4–
d) (1) = HPO5–3 (2) HPO3–
e) (1) = H2PO4– (2) PO4–3
help! don't know what to do
Answers
Answered by
DrBob222
You're over thinking this. Write out the corresponding reactions.
First, it can donate a proton as in
HPO4^2- ==> H^+ + PO4^3-
And it can accept a proton.
HPO4^2- + H^+ ==> H2PO4^-
That's all there is to it. You add a proton or you take away a proton.
First, it can donate a proton as in
HPO4^2- ==> H^+ + PO4^3-
And it can accept a proton.
HPO4^2- + H^+ ==> H2PO4^-
That's all there is to it. You add a proton or you take away a proton.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.