Asked by Priyanka

A pole-vaulter of mass 59.9 kg vaults to a height of 5.9 m before dropping to thick padding placed below to cushion her fall.

(a) Find the speed with which she lands.
m/s



(b) If the padding brings her to a stop in a time of 0.48 s, what is the average force on her body due to the padding during that time interval?
N

I have no clue how to even start this! If someone could help, then please; I would appreciate it!
Answered by bobpursley
a. find the speed from the height he fell.

b. force*time=mass(changeinVelocityatImpact)
Answered by Priyanka
Do I use kinematic equation for part a?
And what would be the force for part b?





Thank you!
Answered by Elena
From the law of conservation of energy:
PE = KE
mgh = mv^2/2
v=sqr(2gh)=sqr(2•9.8•5.9)=10.75 m/s

F=ma=m•Δv/Δt=59.9•10.75/0.48=1342 N
Answered by Priyanka
Thank you Elena :) !
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