The velocity achieved after going a distance X while accelerating at a rate a, from a standing start, is
V = sqrt (2 a X)
Rearrange that equaiton to arrive at the acceleration "a" needed to achieve velocity V at runway distance X:
2aX = V^2
a = V^2/(2X)
An airplane must achieve a velocity of 71 m/s to takeoff. If the runway is 1000 m long, at what speed must the plane constantly accelerate?
Can you show the formula for how you found the answer and explain how to do it.
3 answers
2.52 m/s^2 is what I got...its a choice on the paper
Thanks
Thanks
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