Asked by Amanda
A law firm has thirteen senior and nine junior partners. A committee of 6 partners is selected at random to represent the firm at a conference. What is the probability that at least one of the junior partners is on the committee?
Answers
Answered by
Reiny
Looks like you want us to do an assignment for you.
I will do this last one, but then you must show us that you have some kind of method for doing these.
number of possible committees
= C(22,6) = 74613
number with NO junior partners = C(13,6) = 1716
so the number with at least one junior = 74613-1716 = 72897
prob of at least one junior = 72897/74613 = 6627/6783= 2209/2261 = appr .977
I will do this last one, but then you must show us that you have some kind of method for doing these.
number of possible committees
= C(22,6) = 74613
number with NO junior partners = C(13,6) = 1716
so the number with at least one junior = 74613-1716 = 72897
prob of at least one junior = 72897/74613 = 6627/6783= 2209/2261 = appr .977
Answered by
Amanda
i want help understanding how to solve the problems, not just the answers. I understand how to get the denominator, by getting the total and nCr the sample, but i cannot figure out the numerator when it comes to solving these probability problems.
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