Asked by James

Say, for example, that you had prepared a Buffer C, in which you mixed 8.203 g of sodium acetate, NaC2H3O2, with 100.0 mL of 1.0 M acetic acid.
a. What would be the initial pH of Buffer C? HOW???????

Answers

Answered by DrBob222
See your other posts. Please don't change screen names. It takes us long to answer.
Answered by Anonymous
•8.203 g*(1mol/82.024g)=0.1mol/.1L=1.0 M NaC2H3O2
•pH= pKa+log⁡[NaC_2 H_3 O_2 ]/[acetic acid]
•pH= -log⁡ (1.8x10^-5)+log⁡(1.0 M NaC2H3O2)/(1.0 M acetic acid))= 4.75
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