Asked by Krista
If you step on your car's brakes hard, the wheels stop turning (i.e., the wheels "lock") after 1.5 revolutions.
At the same constant acceleration, how many revolutions do the wheels make before stopping if your initial speed is twice as high?
At the same constant acceleration, how many revolutions do the wheels make before stopping if your initial speed is twice as high?
Answers
Answered by
bobpursley
wf^2=wi^2+2A*displacement
A= -wi^2/2(1.5rev)
if initial speed is the doubled, then w^2 term in the numerator is x4, so rev must be x4 to keep A constant.
so 4x1.5=6rev
A= -wi^2/2(1.5rev)
if initial speed is the doubled, then w^2 term in the numerator is x4, so rev must be x4 to keep A constant.
so 4x1.5=6rev
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