Use the expressions for left and right sums and the table below.

Question

right-hand sum = summation (n above and i =1 on the bottom) f(ti) * change in t = f(t1) * change in t + f(t2) * change in t + .... + f (tn) * change in t
left-hand sum = summation (n above and i = 0 on the bottom) f(ti) * change in t = f (t0) * change in t + f (t1) * change in t + ... = f (tn - 1) * change in t.

Table: t 0 4 8 12 16
f (t) 26 24 23 21 18
If the table messed up, the points are (0, 26), (4, 24) , (8, 23) , (12, 21), (16, 18)

a.) If n = 4, what is change in t? What are t0, t1, t2, t3, t4? What are f (t0), f (t1), f (t2), f (t3), f(t4)?
t0= f (t0) =
t1 = f (t1) =
t2 = f (t2) =
t3 = f (t3) =
t4 = f (t4) =

b.) Find the left and right sums using n = 4.
Left sum =
Right sum =

c.) If n = 2, what is change in t? What are t0, t1, t2? What are f (t0), f (t1), f(t2)?
t0 = f (t0) =
t1 = f (t1) =
t2 = f (t2) =

d.) Find the left and right sums using n = 2
Left sum =
Right sum =

Please show work and explain. I have a couple more problems like this and I don't know how to do them!