Asked by Maggie
A 20.0 mL sample of an aqueous HClO3 solution is titrated with a 0.0275 M KOH solution. The equivalence point is reached with 28.5 mL of the base. The pH of the HClO3 solution, before titration, is
Answers
Answered by
DrBob222
From the titration data you determine the M HClO3.
mL HClO3 x M HClO3 = mL NaOH x M NaOH.
Then given the HClO3 concn,
(H^+) = (HClO3) and
pH = -log(H+)
mL HClO3 x M HClO3 = mL NaOH x M NaOH.
Then given the HClO3 concn,
(H^+) = (HClO3) and
pH = -log(H+)
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