Asked by Brittany
I can't do the following problem. I am not sure what to do when you have an algerbraic power & have to multiple it by a real number?
((x^ny^(m+3))^2)/x^(n+2)y^3-m)) * ((x^2y)/(x^(n-5)*y^(5-3m))
((x^ny^(m+3))^2)/x^(n+2)y^3-m)) * ((x^2y)/(x^(n-5)*y^(5-3m))
Answers
Answered by
Reiny
remember that when multiplying powers with the same base, we keep the base and ADD the exponents, and when dividing powers we
SUBTRACT the exponents.
my second line to your solution would be
x<sup>2n+2-n-2-n+5</sup> y<sup>2m+6+1-3+m-5+3m</sup>
= x<sup>5</sup>y<sup>2</sup>
I hope I interpreted your expression correctly, since there appears to be an extra ")" in the part before the "*"
SUBTRACT the exponents.
my second line to your solution would be
x<sup>2n+2-n-2-n+5</sup> y<sup>2m+6+1-3+m-5+3m</sup>
= x<sup>5</sup>y<sup>2</sup>
I hope I interpreted your expression correctly, since there appears to be an extra ")" in the part before the "*"
Answered by
Reiny
make that
= x<sup>5</sup>y<sup>2+6m</sup>
I guess it was anticipated wishfull thinking that the m's would also cancel
= x<sup>5</sup>y<sup>2+6m</sup>
I guess it was anticipated wishfull thinking that the m's would also cancel
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