Asked by Tarkan
Fnet= F1+F2+F3, F1=40N with bearing of 90' , F2=25N with bearing of 30' ,and F3= 12N with bearing of 290' what is the magnitude and direction ....using VECTOR COMPONENTS....
Answers
Answered by
Steve
F1 = 0i+40j
F2 = 21.65i + 12.5j
F3 = 4.10i - 11.28j
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Fnet = 25.75i + 41.22j
= 48.60 at 50°
F2 = 21.65i + 12.5j
F3 = 4.10i - 11.28j
-------------------
Fnet = 25.75i + 41.22j
= 48.60 at 50°