Question
An experiment was carried out to determine the value of the equilibrium constant Kc for the reaction.
Total moles of Ag+ present = 3.6 x 10-3 moles
Total moles of NH3 present = 6.9 x 10-3 moles
Measured concentration of Ag(NH3)2+ at equilibrium= 3.4* 10-2 M
Total solution volume = 100 mL
(a). Calculate the equilibrium concentration of Ag+ (uncomplexed).
(b). Calculate the equilibrium concentration of NH3 (uncomplexed).
(c). Calculate the value of the equilibrium constant (Kc).
I GOT 1.7*10^7 for question C. IS IT RIGHT?????????
Total moles of Ag+ present = 3.6 x 10-3 moles
Total moles of NH3 present = 6.9 x 10-3 moles
Measured concentration of Ag(NH3)2+ at equilibrium= 3.4* 10-2 M
Total solution volume = 100 mL
(a). Calculate the equilibrium concentration of Ag+ (uncomplexed).
(b). Calculate the equilibrium concentration of NH3 (uncomplexed).
(c). Calculate the value of the equilibrium constant (Kc).
I GOT 1.7*10^7 for question C. IS IT RIGHT?????????
Answers
What's the reaction? I'm guessing at
Ag^+ + 2NH3 ==> Ag(NH3)2^+
If that's the reaction my number is 1.75E7 which I would round to 1.8E7 instead of your 1.7E7. Good work.
Ag^+ + 2NH3 ==> Ag(NH3)2^+
If that's the reaction my number is 1.75E7 which I would round to 1.8E7 instead of your 1.7E7. Good work.
THANX
uju
How
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