Question

x^3-6x^2+17x

Find the point of inflection of the graph of the function?
x,y ( , )


I tried to solve for it by getting the 1st derivative and setting it equal to 0 but i get sqrt,so am confused!

Answer 1

for the point of inflection you need the second derivative equal to zero

y = x^3 - 6x^2 + 17x
y' = 3x^2 - 12x + 17
y'' = 6x - 12

6x-12=0
x = 2

then y = 8 - 24 + 34 = 18

point of inflection is (2,18)

Answer 2

Thank you :)!