Question

A small object with mass 4.05 kg moves counterclockwise with constant speed 1.70 rad/s in a circle of radius 3.15 m centered at the origin. It starts at the point with position vector 3.15 m. Then it undergoes an angular displacement of 9.10 rad.
(a) What is its new position vector?

Answer 1

r cos(angular displacement) =i
r sin(angular displacement) =j
3.15m * cos(9.10 rad) = -2.98
3.15m * sin(9.10 rad) = 1.01
(-2.98i+1.01j)m