Asked by Elli

f(x)=x^3-3x^2-3x-8/(-3x^2-4x-6)
Find the equation of the non-vertical asymptote.
What is the smallest value of x at which f(x) intersects its non-vertical asymptote?
Answered by Steve
since for large x, f(x) just looks like x^3/-3x^2, the asymptote is y = -x/3

So, how to find there the curve intersects the asymptote? Duh. Set the two equal:

(x^3-3x^2-3x-8)/(-3x^2-4x-6) = -x/3

It appears they do not intersect. Typo?
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