Question
The point (5,-2) lies on the graph of y=f(x), and assume f^-1(x) exists. Find the corresponding point on eAch graph.
A). Y=f^-1(x)
I get (-5,2)
B). Y=-f^-1(-x)+4
I get (5,2)
C). Y=f^-1(x+2)+3
I get (-7,5)
Did I get these right?
A). Y=f^-1(x)
I get (-5,2)
B). Y=-f^-1(-x)+4
I get (5,2)
C). Y=f^-1(x+2)+3
I get (-7,5)
Did I get these right?