Ask a New Question

A particle moves from the origin to the point x = 3.0 m, y = 15 m along the curve y =ax^2 - bx, where a = 3.0 m^{-1} and b = 4.0. It is subject to a force vector F = cxyi +dj, where c = 10 N/m^2 and d = 18 N. Calculate the work done by the force.

Similar Questions

A PARTICLE OF MASS M IS SHOT WITH an initial velocity v making an angle b with the horizontal,the particle moves in the
1. 1 answer
a particle moves along x axis.its acceleration (a) at any time is given by a= A+BV^2 where A and B are constants and v is
1. 1 answer
A particle P starts at the origin (x0,y0)=(0,0), of the plane. The particle moves in steps as follows.1. P moves 1 unit to the
1. 3 answers
At t=0, a particle leaves the origin with a velocity 6m/s in the positive x direction and moves in the x-y plane with a constant
1. 1 answer

more similar questions