a sports car traveling at 27.8 m/s slows at a constant rate to a stop in 8.00 s. What is the displacement of the sports car in this time interval

Average speed x time = 13.9 * 8.00

= ___ m

111.2m

A sports car traveling at 24.7 m/s slows at a constant rate to a stop in 16.00 s. What is the displacement of the sports car in this time interval?

To find the displacement of the sports car, we need to use the formula for displacement:

displacement = initial velocity * time + (1/2) * acceleration * time^2

Since the sports car is slowing down, its final velocity is 0 m/s. We are given the initial velocity (27.8 m/s) and the time interval (8.00 s). However, to calculate the displacement, we need to know the acceleration.

To find the acceleration, we can use the formula:

acceleration = (final velocity - initial velocity) / time

In this case, the final velocity is 0 m/s, the initial velocity is 27.8 m/s, and the time is 8.00 s. Substituting these values into the formula, we can calculate the acceleration:

acceleration = (0 m/s - 27.8 m/s) / 8.00 s

acceleration = -27.8 m/s / 8.00 s

acceleration = -3.475 m/s^2

Now that we have the acceleration, we can substitute the values into the displacement formula:

displacement = 27.8 m/s * 8.00 s + (1/2) * (-3.475 m/s^2) * (8.00 s)^2

displacement = 222.4 m + (-3.475 m/s^2) * 64.00 s^2

displacement = 222.4 m - 222.4 m

displacement = 0

Therefore, the displacement of the sports car in this time interval is 0 meters.