Average speed x time = 13.9 * 8.00
= ___ m
= ___ m
displacement = initial velocity * time + (1/2) * acceleration * time^2
Since the sports car is slowing down, its final velocity is 0 m/s. We are given the initial velocity (27.8 m/s) and the time interval (8.00 s). However, to calculate the displacement, we need to know the acceleration.
To find the acceleration, we can use the formula:
acceleration = (final velocity - initial velocity) / time
In this case, the final velocity is 0 m/s, the initial velocity is 27.8 m/s, and the time is 8.00 s. Substituting these values into the formula, we can calculate the acceleration:
acceleration = (0 m/s - 27.8 m/s) / 8.00 s
acceleration = -27.8 m/s / 8.00 s
acceleration = -3.475 m/s^2
Now that we have the acceleration, we can substitute the values into the displacement formula:
displacement = 27.8 m/s * 8.00 s + (1/2) * (-3.475 m/s^2) * (8.00 s)^2
displacement = 222.4 m + (-3.475 m/s^2) * 64.00 s^2
displacement = 222.4 m - 222.4 m
displacement = 0
Therefore, the displacement of the sports car in this time interval is 0 meters.