Integral from pi/6 to pi/4 of 2sin(2x)cos(2x)dx=

Answer 1

2sin(2x)cos(2x)=sin(4x) (double angle)
∫sin(4x) dx = -(1/4)cos(4x) evaluated from π/6 to π/4
=-(1/4)cos(4(π/4)-(-1/4)cos(4(π/6)
=1/4-(-1/4(-1/2)
=1/4 - 1/8
=1/8