Asked by James

Write the Gross and Net Ionic Equations for the following Reactions:

LiNO3(aq)+(NH4)3N(aq) => Li3N(s)+ NH4NO3(aq)

Al(s)+CuCl2(aq) => AlCl3(aq)+Cu(s)

Answers

Answered by DrBob222
And you are having trouble doing what?
Answered by James
Yep
Answered by DrBob222
C'mon. Yep won't get it. Exactly what do you not understand?
Answered by James
I'm not sure what it's asking. I know I need to write out the aqueous parts and write the charges, but I don't how to do that. Mostly I need help getting it to the Gross Equation.
Answered by DrBob222
First you balance the molecular equation.
3LiNO3(aq)+(NH4)3N(aq) => Li3N(s)+ 3NH4NO3(aq)

Then convert to a total ionic equation following a few rules as follows:
If the compound is an ionic compound you break it apart into ions. If it is a strong acid or strong base do likewise. If a solid, a gas, or if a weak acid or weak base, write those as molecules.

3Li^+(aq) + 3NO3^-(aq) + 3NH4^+ + N^3-(aq) => Li3N(s)+ 3NH4^+(aq) + 3NO3^-(aq)

That is the total ionic equation. Now you look for ions that are common to both sides; cancel those you find. I see 3 NO3^- on the left and right and I see 3 NH4^+ left and right sides. Cancel those from both sides and you are left with this.
3Li^+(aq) + N^3-(aq) ==> Li3N(s)
That is the net ionic equation. The ions you canceled are called spetator ions; they don't enter into the reaction. I'll be happy to check your work on the next one.
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