Which of the following is the maximum value of the function f(x)=2sinxcosx?

a) 0

b) 1

c) 2

d) No maximum value

1 answer

since 2sinx cosx = sin(2x), it has a max of 1. sin(u) has a min/max of 1 regardless of what u is.
Similar Questions
  1. Is this correct?(sinx - cosx)^2 = 1 - 2sinxcosx LS = sin^2x - 2sinxcosx + cos^2x = 1 - cos^2x - 2sinxcosx + cos^2x = 1 - cos^2x
    1. answers icon 0 answers
  2. Is this correct?(sinx - cosx)^2 = 1 - 2sinxcosx LS = sin^2x - 2sinxcosx + cos^2x = 1 - cos^2x - 2sinxcosx + cos^2x = 1 - cos^2x
    1. answers icon 1 answer
  3. solve algebraically, express the roots in exact form2sinxcosx-1=0 I got: 2sinxcosx=1 sin^2x=1 what do I do next? thanks in
    1. answers icon 0 answers
  4. Prove the identity:1-cos2x/sin2x = 1+tanx/1+cotx I simplified the RS to tanx. LS:(1-2cos²x+1)/2sinxcosx (2+2cos²x)/2sinxcosx
    1. answers icon 2 answers
more similar questions