Asked by J
                (a) How much charge does a battery have to supply to a 5.0 uF capacitor to create a potential difference of 1.5 V across its plates?  How much energy is stored in the capacitor in this case? (b) How much charge would the batter have to supply to store 1.0 J of energy in the capacitor?  What would be the potential across the capacitor in this case.
Once again, I am lost!!!
            
        Once again, I am lost!!!
Answers
                    Answered by
            Damon
            
    a) C = q/V so q = C V
= 5*10^-6 * 1.5
= 7.5 * 10^-6 Coulombs
now do E = (1/2) C (1.5)^2 to get energy
E = .5 (5*10^-6)(2.25)
E = 5.63*10^-6 Joules
b) Luckily we derived this in your last question, but now that I see your questions you probably have it in your book and have not had calculus so
E = (1/2) C V^2 from your book or the other problem
E = (1/2) C (q/C)^2
(q/C)^2 = 2 E/C
q^2/C^2 = 2 E/C
q^2 = 2 E C
q = sqrt (2E*C)
q = sqrt (2 * 5 * 10*-6)
q = 10^-3 sqrt (10)
q = 3.16 * 10^-3 coulombs
c)V = q/C = 2.24*10^-3 / 5*10^-6
V = .447* 10^3 = 447 volts, watch out
    
= 5*10^-6 * 1.5
= 7.5 * 10^-6 Coulombs
now do E = (1/2) C (1.5)^2 to get energy
E = .5 (5*10^-6)(2.25)
E = 5.63*10^-6 Joules
b) Luckily we derived this in your last question, but now that I see your questions you probably have it in your book and have not had calculus so
E = (1/2) C V^2 from your book or the other problem
E = (1/2) C (q/C)^2
(q/C)^2 = 2 E/C
q^2/C^2 = 2 E/C
q^2 = 2 E C
q = sqrt (2E*C)
q = sqrt (2 * 5 * 10*-6)
q = 10^-3 sqrt (10)
q = 3.16 * 10^-3 coulombs
c)V = q/C = 2.24*10^-3 / 5*10^-6
V = .447* 10^3 = 447 volts, watch out
                    Answered by
            Mercy
            
    Good but quite difficult to understand. 
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.