P = 2L + 2W
200 = 2(2W - 5) + 2W
200 = 4W - 10 + 2W
200 + 10 = 6W
210 = 6W
35 = W
The perimeter of rectangular playground is 200 feet. If the length is 5 feet less than twice the width, what are dimensions of the playground
2 answers
35