Asked by kevin
Josh starts his sled at the top of a 2.0 m-high hill that has a constant slope of 25 degrees . After reaching the bottom, he slides across a horizontal patch of snow. The hill is frictionless, but the coefficient of kinetic friction between his sled and the snow is 0.07.
Answers
Answered by
drwls
If the snow on hill is frictionless it should also be frictionless on the level patch. This is a very artificial contrived problem. But let's do it anyway.
KE at bottom = M g H = Friction * (slide distance X)
M g H = M g*0.07*X
X = H/0.07 = 28.5 meters
KE at bottom = M g H = Friction * (slide distance X)
M g H = M g*0.07*X
X = H/0.07 = 28.5 meters
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