Asked by Keisha

If 4.00 g of metal is plated in the voltaic cell (which contains Ag and Ni with the total potential of 2.98 V) , how much metal is plated in the electrolytic cell (contains Ag and Zn with the total of 1.98 V)?

I have no idea how to do this! Help?
Answered by Keira
if you had 3.00 g in the question

3.00g(mol/g108)(1molZn/2)(65g/mol)= 0.91g