Asked by Erikan Attah
using chain rule find the derivative of y=xsin1/x
Answers
Answered by
bobpursley
y' = sin(1/x) dx/dx + x d(sin(1/x))/dx
= sin (1/x)+ x cos(1/x)d(1/x)/dx
= sin (1/x)+ x cos(1/x)(-1/x^2)
= sin(1/x) - (1/x)cos(1/x)
= sin (1/x)+ x cos(1/x)d(1/x)/dx
= sin (1/x)+ x cos(1/x)(-1/x^2)
= sin(1/x) - (1/x)cos(1/x)
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