what don't you get?
T4 = a+3d
T6 = a+5d
a+3d + a+5d = 42
2a + 8d = 42
a+4d = 21
T3 = a+2d
T9=a+8d
a+2d + a+8d = 52
2a + 10d = 52
a+5d = 26
a+4d = 21
a+5d = 26
d = 5
so a=1
sum of T1-T10 = 10/2(1+46) = 235
AP = 1 6 11 16 21 26 31 36 41 46 . . .
the sum of the 4th and 6th terms of an A.P is 42. the sum of the 3rd and 9th terms of the progression is 52. find the first term, the common difference and the sum of the first ten terms of the progression.
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Answer
I need freaking help right now and this is not helping me!!!!!
it is not helping matters
1 answer