A wooden box weighing 271 N is pushed across the floor by a workman who exerts a horizontal force of 144 N. If the force of friction between the box and the floor is 28 N, what is the acceleration (in meters/second^2) of the box?

Answer 1

a = Fnet/M = (144-28)/M = 116/M

The mass is M = 271/g = 27.65 kg

a = 116/27.65 = 4.19 m/s^2