Ask a New Question

Question

A wet bar of soap slides freely down a ramp 12.0 m long, inclined at 74.0 degrees. How long (in seconds) does it take to reach the bottom? (Neglect friction.)
13 years ago

Answers

drwls
acceleration rate (with no friction) = a = g*sin74 = 9.43 m/s^2

(a/2)t^2 = 12.0 m
Solve for t

t = 1.60 s
13 years ago
Anonymous
A wet bar of soap slides down a ramp 10.0 m long inclined at 11.73°. What would be its final velocity upon reaching the bottom of the incline? Assume coefficient of kinetic friction 0.06.
4 years ago

Related Questions

in what direction will a freely suspended magnet come to rest? in what direction will a freely suspended magnet come to rest?-how can you determine which direction... A wet bar of soap slides freely down a ramp 2.0 m long inclined at 6.8o. How long does it take to re... a 2kg and a 4kg hang freely at opposite end of a light in-extensible string which passes over a smal... A wet bar of soap slides down a ramp 9.4 m long inclined at 8.0∘ . How long does it take to reach... 3. Consider a freely falling object. a. What is the acceleration (in m/s2) after 5 seconds of fall?... A wet bar of soap slides down a ramp 5.3-m long inclined at 4.9o. How long (in seconds) does it take... Why do so many people freely cheat here? When resources are not freely available in amounts sufficient to satisfy all desired uses for them... An object falls freely near Earth's surface. Which graph best represents the relationship between th...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use