A wet bar of soap slides freely down a ramp 12.0 m long, inclined at 74.0 degrees. How long (in seconds) does it take to reach the bottom? (Neglect friction.)

Answer 1

acceleration rate (with no friction) = a = g*sin74 = 9.43 m/s^2

(a/2)t^2 = 12.0 m
Solve for t

t = 1.60 s

Answer 2

A wet bar of soap slides down a ramp 10.0 m long inclined at 11.73°. What would be its final velocity upon reaching the bottom of the incline? Assume coefficient of kinetic friction 0.06.