Asked by Jane
Suppose that the amount of algae is a pond doubles every 3 hours. If the pond initially contains 70 pounds of algae, how much algae will be in the pond after 9 hours?
Is the answer 560? I was not sure how to set it up, but doubled it every 3 hours. If this is not correct, please show me how to solve.
Is the answer 560? I was not sure how to set it up, but doubled it every 3 hours. If this is not correct, please show me how to solve.
Answers
Answered by
Steve
population p = 70*2^(n/3) after n hours
70 * 2^3 = 70*8 = 560
70 * 2^3 = 70*8 = 560
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