Asked by Tracy
A lukewarm bottle containing 800 grams of water is placed in a refrigerator. How many calories of heat must be removed from that water to chill its temperature from 55 c to 4 c?
Q = m(c)(delta t)
Q = (100g)(1.0 c/g*c)(51c) = 40,800
Is the answer correct?
Q = m(c)(delta t)
Q = (100g)(1.0 c/g*c)(51c) = 40,800
Is the answer correct?
Answers
Answered by
bobpursley
Correct.
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