Asked by Darren
(x^3+8) x ((x-2)/(x^2-2x+4))/ (x^2-4)/(x-6)
Answers
Answered by
Steve
you have
(x+2)(x^2-2x+4) * (x-2)(x^2-2x+4) / (x+2)(x-2)(x-6)
(x^2-2x+4)^2 / (x-6)
(x+2)(x^2-2x+4) * (x-2)(x^2-2x+4) / (x+2)(x-2)(x-6)
(x^2-2x+4)^2 / (x-6)
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