Asked by oris

Consider the low-speed flight of the Space Shuttle as it is nearing a landing. If the air
pressure and temperature of the shuttle are 1.2 atm and 300 K, respectively, what is the
air density? Note: 1 atm = 101325 N/m^2. Hint: Use ideal gas law!

Answers

Answered by drwls
Take the hint.

Density = P/(RT)

R = 0.08205 liter*atm/(mole*K)

Use P = 1.2 atm. That will give you the density in mole/liter

Air has 28.9 grams per mole
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