Asked by Anonymous

1)100ml sample of solution that is 0.2m in both Naf and Hf has 4.0 ml of 1.0m hcl added to it. calculate the ph change of this soultion .ka =7.2*10^-4


2)40 ml of 0.32m benzoic acid if titrated with 60 ml of 0.2 m naoh. clacilate the ph of the resulting solution at the equivalence point. ka =4.9*10^-9

Answers

Answered by DrBob222
Do you know the difference between m and M? Should these concns be m or M?
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