Explain how the graph of sin2 theta relates to y=sin theta

Graph y=-sin2(x-(3.14/4))

sin2 =2tan cos

cos2Acos2B + sin²(A-B) - sin²(A+B) = cos(2A+2B)

If sin(θ) = -1/√2, find sin2(θ). (Recall that sin2(θ) means (sin(θ))2.) sin2(θ) =

ʃ sin² cos² dx

Are these the solutions to sin2x sinx = cosx? pi/2, 3pi/2, 3pi/4, pi/4, 7pi/4, 5pi/4

how to graph y= sin2(x+1) and y =cos 10(x+3) I know how to find amplitude period phase shift and Ve...

does sin2(x)=sin(2x)?

Sin2 theta =-1

Sin²(x)=0.25

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