f(x)=px^3 + 6x^2 + 12x + q
given that the remainder when f(x) is divided by (x - 1) is equal to the remainder when f(x) is divided by (2x + 1),
(a) find the value of p.
given also that q = 3, and p has the value found in part (a)
(b) find the value of the remainder.
my working out for (a) is
f(1)=p(1)^3 + 6(1)^2 + 12(1) + q
= p + 6 + 12 + q
= p + 18 = q
then I get stuck. Please help.
2 answers
Do the same thing you did before using -1/2 for x. (2x+1=0 and solve for x) Then you will have two equations and two unknowns and you can solve for p
Like simultaneous equations?
p + 18 + q = 1/8p - 4.5 +q
I get -25.71..... Is this right?
p + 18 + q = 1/8p - 4.5 +q
I get -25.71..... Is this right?
0 answers