Asked by peter

f(x)=px^3 + 6x^2 + 12x + q

given that the remainder when f(x) is divided by (x - 1) is equal to the remainder when f(x) is divided by (2x + 1),

(a) find the value of p.

given also that q = 3, and p has the value found in part (a)

(b) find the value of the remainder.

my working out for (a) is

f(1)=p(1)^3 + 6(1)^2 + 12(1) + q

= p + 6 + 12 + q

= p + 18 = q

then I get stuck. Please help.

Answered by BOB
Do the same thing you did before using -1/2 for x. (2x+1=0 and solve for x) Then you will have two equations and two unknowns and you can solve for p
Answered by peter
Like simultaneous equations?

p + 18 + q = 1/8p - 4.5 +q

I get -25.71..... Is this right?
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