Asked by Anonymous
an ap consists of 21 terms.the sum of 3terms in the middle is 129 and of the last three is 237 find the AP.
Answers
Answered by
Bria
21terms/3terms=7groups of 3terms
237(last group)-129 (middle group)=36
237(group7)-36=201(group6)
group6-36
group5-36
129(group4)-36=95(group3)
group3-36
group2-36
add up all group terms(237+201+165...)
Hope that's what your looking for if not sorry, but that should be right
237(last group)-129 (middle group)=36
237(group7)-36=201(group6)
group6-36
group5-36
129(group4)-36=95(group3)
group3-36
group2-36
add up all group terms(237+201+165...)
Hope that's what your looking for if not sorry, but that should be right
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