Asked by ALISON
Determine the pH of each solution:
(a) 0.10 M NH4Cl
can someone show me how to do this one so i have the idea of how to do the rest. thanks!
(a) 0.10 M NH4Cl
can someone show me how to do this one so i have the idea of how to do the rest. thanks!
Answers
Answered by
DrBob222
The pH of salts is determined by the hydrolysis of the salt. In the case of NH4Cl, the NH4^+ is hydrolyzed because it is a stronger acid than H2O (the NH4^+ donates a H^+ to H2O).
.........NH4^+ + H2O ==> H3O^+ + NH3
.........0.1...............0......0
change....-x...............x......x
equil....0.1-x.............x......x
Ka for NH4^+ = (Kw/Kb for NH3) = (H3O^+)(NH3)/(NH4+)
Substitute from the ICE chart and solve for x which is H3O^+, and convert that to pH.
.........NH4^+ + H2O ==> H3O^+ + NH3
.........0.1...............0......0
change....-x...............x......x
equil....0.1-x.............x......x
Ka for NH4^+ = (Kw/Kb for NH3) = (H3O^+)(NH3)/(NH4+)
Substitute from the ICE chart and solve for x which is H3O^+, and convert that to pH.
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