Asked by Anonymous
finding the square x^2+16x=0
Answers
Answered by
MathGuru
Complete the Square:
x^2 + 16x = 0
x^2 + 16x + (16/2)^2 − (16/2)^2 = 0
x^2 + 16x + 64 = 64
(x + 8)^2 = 64
x + 8 = + or - √64
x + 8 = 8; x + 8 = -8
Therefore:
x = 0, −16
Check with the original equation. It always helps to check your work!
x^2 + 16x = 0
x^2 + 16x + (16/2)^2 − (16/2)^2 = 0
x^2 + 16x + 64 = 64
(x + 8)^2 = 64
x + 8 = + or - √64
x + 8 = 8; x + 8 = -8
Therefore:
x = 0, −16
Check with the original equation. It always helps to check your work!
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